You have
.. f'(u) = sec(u)^2
Putting in u = g(x) = x^9, this becomes
.. f'(g(x)) = sec(x^9)^2
You know
(f(g(x))' = f'(g(x))*g'(x) . . . . . chain rule
From previous results, this is
.. sec(x^9)^2*9x^8
Answer:
2
Step-by-step explanation:
hello
the points given are (-4, 47) and (2, -16)
let's find the intercept of this equation


now, since we know the value of the slope, we can use that in the standard equation on a straight line
the standard equation of a straight line is given as

we can pick any of the points and solve for intercept
let's use (2, -16)

now we know the value of intercept (c) = 5 and the slope (m) = 21/2
let's use this to write equation of the straight line

from the calculations above, the equation of the straight line is given as y = -21/2x + 5
Answer:
5
Step-by-step explanation:
evaluate f(4) by substituting x = 4 into f(x) and g(2) by substituting x = 2 into g(x)
f(4) = (3 × 4) - 3 = 12 - 3 = 9
g(2) = (2 × 2 ) = 4
f(4) - g(2) = 9 - 4 = 5
There are 1000 millilitres in a litre so that is 2.7 litres. 2.7 to the nearest litre is 3 litres.