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gayaneshka [121]
3 years ago
15

How many fifths must be added to 6/10 to make a whole​

Mathematics
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

2/5

Step-by-step explanation:

10/10 = 1 Whole

You need 4/10 to get 1 whole

4/10 is equivalent to 2/5 because when you divide the numerator and denominator by 2 you the 2/5.

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There are 8 roses in a vase of 13 flowers. The rest are daisies.
Blizzard [7]

Answer:

  1. 5:13
  2. 8:5

Step-by-step explanation:

For first part:

  1. Roses = 8
  2. Daises = All flowers - Roses
  3. Daises = 13 - 8
  4. Daises = 5
  5. Daises:All Flowers = 5:13

For second part:

  1. Roses:Daises = 8:5

I hope this helps!

7 0
3 years ago
Read 2 more answers
What is the distance between the points (−5, −9)(−5, −9) and (−5, 13)(−5, 13) ?
krok68 [10]
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(-5,-9)...x1 = -5, and y1 = -9
(-5,13)...x2 = -5 and y2 = 13
now we sub and solve
d = sqrt (-5 - (-5)^2 + (13 - (-9)^2
d = sqrt (-5 + 5)^2 + (13 + 9)^2
d = sqrt (0^2 + 22^2)
d = sqrt (484)
d = 22 <==
6 0
3 years ago
Reggie, Alvin, and Jose are member of a relay running team. Reggie finished his leg of the race 2.45 seconds faster than Alvin a
lorasvet [3.4K]
From the given, we expressed the time that each of the team members ran in mathematical expression.
 
                Reggie = 57.12 seconds
                 Alvin = 57.12 + 2.45 seconds = 59.57 seconds
                 Jose = 57.12 - 3.81 seconds = 53.31 seconds
We then sum up all the time we calculate to determine the total time for the team. The answer is therefore 170 seconds. 
8 0
3 years ago
Helpppppppppppppppppppppppppppppppppppp
Alexxandr [17]
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical. 
First, lets factor 8:
8=2 ^{3}
Now we can divide the power of the term, 3, by the index of the radical 2:
\frac{3}{2} = 1 with a remainder of 1
Next, lets do the same for our second term x^{7}:
\frac{7}{2} = 3 with a remainder of 1
Again, lets do the same for our third term y^{8}:
\frac{8}{2} =4 with no remainder, so this term will come out completely.

Finally, lets take our terms out of the radical:
\sqrt{8x^{7} y^{8}  }= \sqrt{ 2^{3} x^{7} y^{8}   }  =2 x^{3}  y^{4}  \sqrt{2x}

We can conclude that the correct answer is the third one. 

4 0
3 years ago
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Hey can you please me asap!
crimeas [40]

Answer:

It's D

Step-by-step explanation:


6 0
3 years ago
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