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Vaselesa [24]
3 years ago
12

Definition for equations

Mathematics
1 answer:
MissTica3 years ago
3 0
Here’s your definition

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Please help I really need it
lesya692 [45]

Answer:

Shanice

Step-by-step explanation:

<u>Michael</u>

4 1/4 times 3 = 12 3/4

<u>Shanice</u>

2 3/4 times 5 = 13 3/4.

Now we have to find the difference so

13 3/4 - 12 3/4 = 1

Therefore Shanice runs more miles in a week!  

4 0
3 years ago
Solving each proportions 10/8=n/10
RideAnS [48]

Answer:

n=12.5

Step-by-step explanation:

10/8=n/10

multiply the denominator and numerators 10 ad 10=100 divide by 8=12.5

3 0
3 years ago
A state park has two pools. The olympic size pool holds 8.12 x 10^5 gallons of water and the smaller pool holds 5.27 x 10^5 gall
Ainat [17]

B) 1.339 x 10^6 gallons. When you add 812,000 to 527,000 you get 1,339,000, and to write that in scientific notation you need to make the number less than 10 and more than 1, which is 1.339 and to get the 1,339,000 you need to multiply 1.339 by 10^6.

4 0
3 years ago
Please Please Please help me with the answer
Tems11 [23]

c = amount of chocolate donuts

m = amount of maple donuts.

so we know the total in all is 41 donuts, thus c + m = 41.

we also know that whatever c is, m is 25 fewer than that, m = c - 25.

\bf \begin{cases} c+m=41\\ \boxed{m}=c-25\\ --------\\ c+\boxed{c-25}=41 \end{cases} \\\\\\ 2c-25=41\implies 2c=66\implies c=\cfrac{66}{2}\implies c=33 \\\\\\ \stackrel{\textit{since c = 33}}{m = c - 25}\implies m=33-25\implies m = 8

6 0
3 years ago
Read 2 more answers
Solve 2x^2 + x - 4 = 0 <br> X2 +
damaskus [11]

Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
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