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IceJOKER [234]
3 years ago
5

In order to become a member of the library-all-star-members club, there is a $40 sign-up fee and a $2 monthly fee. Write an equa

tion in slope-intercept form that models this situation.
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0
Assuming f(x) is the cost and X is the number of months.

f(x)=2x+40
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Compare the average rate of change for both functions over the interval [0,3].
Verizon [17]
So find g(0) and g(3)
G(0) = 0^2 -5(0) +3 = 3
And g(3) = 3^2 - 5(3) +3 = 9 - 15 + 3 = 3 so there is no change in g(x) for that interval.

H(0) = 8(0) + 10 = 10
And h(3) = 8(3) + 10 = 34
So the change in h(x) for that interval is 24.
5 0
2 years ago
5 1/3-3 2/4 find the difference
Vinil7 [7]

Answer:

1 10/12

Step-by-step explanation:

Take the fractions and get them to the same bottom number, 12.  So it would be 5 4/12 -  3 6/12.

Take 1 away from 5 to get 4 and the one you pulled would be 12/12(also equal to 1).  4  16/12 - 3  6/12 would be 1  10/12

8 0
3 years ago
Please help me with this. It needs to be done soon, so I’d appreciate anyone who answers this.
creativ13 [48]

Answer:

A. 4 1/2 ==+ 3

B. 2 + 4

C. 1/2 + 1/2

D. 2 1/2 + 1

E. 4 1/2 + 2

Step-by-step explanation:

Read the coordinates and just like figure out the order which it's like 1 through 5 but wit fractions. hope this helps.

8 0
2 years ago
What is the opposite sides of a parallelogram
ICE Princess25 [194]

Answer:


Step-by-step explanation:

Example:  Suppose you have a rectangle of length 8 and width 6.  This figure is also a parallelogram.  There are two sides that are of length 6; these are the "opposite sides" of the parallelogram.  There are two sides that are of length 8; these are also "opposite sides" of the parallelogram.  

8 0
3 years ago
Given that the contracts are awarded​ independently, find the probability that the company will get both contracts. recall ​p(la
VladimirAG [237]
If those percentiles are the changes of the two contracts occurring, it would be <span>0.31 *0.64 = </span>0,1984 

3 0
3 years ago
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