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oksian1 [2.3K]
3 years ago
13

1. During October, William Korth worked 160 regular time hours at $9.28 an hour and 18 overtime hours at time-

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0

Answer:

Kindly check explanation

Step-by-step explanation:

1.) regular time hours = 160

Overtime hours = 18

Gross pay = (9.28 * 160) + (1.5 * 9.28 * 18) = $1735.36

2.) Last year, Ida Zolen worked 2,000 hours at regular time pay of $8.20 an hour. She also worked 75 hours over time at double his regular rate. What was Ida’s gross pay last year?

Gross pay:

(2000 * 8.20) + (2 * 8.20 * 75) = $17,630

3. Alan Kirbaum works on an 8-hour day basis and is paid $8 an hour for regular time work and time-and-a half for overtime work. Last week he worked these hours: Monday:9 ; Tuesday:6 ; Wednesday:11 ; Thursday:8 ; Friday:9.

A) How many regular hours did he work?

Regular hours = (8 + 6 + 8 + 8 + 8).= 38 hours

B) How many overtime?

Overtime = (1 + 3 + 1). = 5 hours

C) What is his overtime rate?

2.5 * $8 = $20

D) What is his overtime pay?

$20 * 5 = $100

E) Find Alan’s gross pay.

(38 * $8) + $100 = $404

4. Stephen Woll’s regular pay is $20 an hour. He is paid time and a half for overtime work beyond 40 hours a week. He

worked: Monday:11 ; Tuesday:10 ; Wednesday:10 ; Friday:12. Find Stephen

Total Hour = (11 + 10 + 10 + 12) = 43 hours

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timofeeve [1]
D 42 units hope I helped
5 0
3 years ago
Ryan is looking for the sum of the cube of a number, n, and 16 What is the sum Ryan is looking for if n=2?
mihalych1998 [28]

Answer: The sum =14

Step-by-step explanation:

Given that n=2

And

sum = cube of a number, n, and 16 which can be expressed mathematically as

n^3 + 6

2^3 + 6

8 + 6= 14

6 0
3 years ago
A 65 ft. long swimming pool is to be constructed. The pool will be 4 ft. deep at one end and 11 ft. deep at the other. To the ne
pishuonlain [190]

Answer:

Measure of the acute angle = 84°

Step-by-step explanation:

In the figure attached,

ABDE is a swimming pool having length 'AB' = 65 feet

Depth of one end of the pool is BE = 4 feet

And depth of the other end AD = 11 feet

Acute angle between the bottom of the pool (DE) and wall of the deep end (AD) is ∠ADE.

Now from ΔCDE,

tanx = \frac{EC}{DC}

tanx = \frac{7}{65}

x = \text{tan}^{-1}(\frac{7}{65})

x = 6.15°

Now measure of acute angle the bottom of the pool makes with wall at he deep end,

m∠ADE = (90 - 6.15)°

             = 83.85°

             ≈ 84°

3 0
3 years ago
9.2 HW Central Angles, Arc Measures, & Arc Length
kap26 [50]

Answer:

I can help you with this, i just need the actual questions.

Step-by-step explanation:

5 0
3 years ago
Find the GCF of 207c^3 and 108c^2
geniusboy [140]

Answer:  9c²

<u>Step-by-step explanation:</u>

To find the Greatest Common Factor of 207c³ and 108c², first factor them down to their primes and see what they have in common.

                207c³                     108c²

                 ∧   ∧                        ∧  ∧

             9·23  c·c·c              9·12   c·c

            ∧                            ∧  ∧

           3·3                         3·3 3·4

                                                  ∧

                                                 2·2

                   

207c³: 3·3·23  c·c·c

108c²:  2·2·3·3·3·4 c·c

GCF = 3·3 c·c

        = 9c²

7 0
4 years ago
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