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Trava [24]
3 years ago
9

Find the equation of the line that is perpendicular to y = – 1 4 x – 8 and passes though the point (2, –4).

Mathematics
1 answer:
vivado [14]3 years ago
3 0

The equation of the line is y=\frac{1}{4}x-\frac{29}{7}

Explanation:

The equation of the line is perpendicular to y=-14 x-8

The equation is of the form y=mx+b where m=-14

<u>Slope:</u>

The slope of the perpendicular line can be determined using the formula,

m_1 \cdot m_2=-1

-14 \cdot m_2=-1

       m_2=\frac{1}{14}

Thus, the slope of the line is m=\frac{1}{14}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the slope m=\frac{1}{14} and the point (2,-4), we get,

y+4=\frac{1}{14}(x-2)

Simplifying, we get,

y+4=\frac{1}{14}x-\frac{1}{7}

     y=\frac{1}{14}x-\frac{1}{7}-4

     y=\frac{1}{4}x-\frac{29}{7}

Thus, the equation of the line is y=\frac{1}{4}x-\frac{29}{7}

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