Hello,
Let's x² the square number
and 3*y the multiple of 3.

2 solutions : for (x,y) as integers : (-6,18) and (6,18)
but one solution for (x²,3y) as integers :<u> (36,54) </u>
C=300+1200x-100x. Find x if the total cost is 3,000
3,000 = 300 + 1200x -100x
3000 = 300 + 1100x
2700 = 1100x
2700÷1100=x
x=27/11
x = 2 5/11
Round to 3
N+9
The other factor is n-6
Once multiple together, you will get the same equation again
Answer:
There are 3 different forms of the answer.
Step-by-step explanation:
1. 44/21
2. 2.10
3. 2 2/21