Given that ΔUVW is similar to ΔXYZ, find the length of ZX.

Martene got a small aquarium for her birthday. The aquarium is a right rectangular prism 18.5cm long by 15cm wide. Martene put 3

natita [175]

Equation for this problem: Total 3 cubed / (L x W)

So 18.5cm x 15cm = 277.5 is the product of L and W. Now you need to devide the total by 277.5 which is 14. So the aquarium is 14 cm deep.

7 0

2 years ago

PLEASE I NEED HELP! THANK YOU.

Elden [556K]

First set up a linear equation and using the x and y values in the table see if it solves.

It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)

Using the quadratic formula y = ax^2 +bx +c

Build a set of 3 equations from the table:

C is the Y intercept ( when X is 0), this is shown in the table as 6

Now we have y = ax^2 + bx + 6

-2.4 =4a-2b +6

1.4 = a-b +6

Rewrite the equations

a=b/2 -2.1

1.4 = b/2-2.1 +6

b = 5

a = 5/2 -2.1 = 0.4

replace the letters to get y = 0.4x^2 + 5x +6

4 0

3 years ago

Logan drew 8 hearts and 14 circles. What is the ratio of hearts to all shapes?

lbvjy [14]

Answer:

<h2>ratio is</h2>

Step-by-step explanation:

<h2>4:7 your answer is like this . follow me</h2>

3 0

2 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5-6}{0.2}$

$Z = -5$

$Z = -5$ has a pvalue of 0.

1 - 0 = 1

5 0

3 years ago

HELP PLEASE!!!!

Anestetic [448]

<span>To find her take home pay, you subtract her deductions from her gross pay and then divide her take-home pay by her gross pay and then multiply by 100%.
So,
</span><span>Take-home pay = 2644-548.30=2095.70 Percent = (2095.70/2644)*100%=79.262%
So your answer is </span><span>B)79%
</span><span>Hope this helps :)
If you need anymore help with questions then feel free to ask me :D</span>

4 0

3 years ago