Answer:
the quadratic formula is ax^2 + bx + c", if the first one is expanded out I will be 6x^2+8x+27 so that's the answer
Answer:
m(arc ZWY) = 305°
Step-by-step explanation:
8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,
Angle formed by two tangents = ![\frac{1}{2}(\text{Difference of intercepted arcs})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BDifference%20of%20intercepted%20arcs%7D%29)
= ![\frac{1}{2}(220-140)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28220-140%29)
= ![\frac{1}{2}(80)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2880%29)
= 40°
9). Following the same rule as above,
Angle formed between two tangents = ![\frac{1}{2}(\text{Difference of intercepted arcs})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BDifference%20of%20intercepted%20arcs%7D%29)
125 = ![\frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Bmajor%20arc%7D%29-m%28%5Ctext%7Bminor%20arc%7D%29%5D)
250 = ![[m(\text{arc ZWY})-m(\text{arc ZY})]](https://tex.z-dn.net/?f=%5Bm%28%5Ctext%7Barc%20ZWY%7D%29-m%28%5Ctext%7Barc%20ZY%7D%29%5D)
250 = m(arc ZWY) - 55
m(arc ZWY) = 305°
Therefore, measure of arc ZWY = 305° will be the answer.
10). m(arc BAC) = ![\frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Bm%28%5Ctext%7Barc%20BDC%7D%29-m%28%5Ctext%7Barc%20BC%7D%29%5D%29)
= ![\frac{1}{2}(254-106)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28254-106%29)
= ![\frac{148}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B148%7D%7B2%7D)
= 74°
-13.213203440000000000000
12,870 dollars. Let me know if you want me to show my work.
Answer:
20
The denominators of 3
/10 and 1
/4 are 10 and 4.
The factors of 10 are 2
×
5 and 2
×
2
Therfore the LCD should have two 2's and one 5.
This means the answer is:
2
×
2
×
5
=
<u>20</u>
I hope this helps :)