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Akimi4 [234]
4 years ago
9

A ray that contains a point that is equidistant from both sides of the angle. *

Mathematics
1 answer:
seraphim [82]4 years ago
3 0
<span>Consider a angle â BAC and the point D on its defector Assume that DB is perpendicular to AB and DC is perpendicular to AC. Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC Proof Consider triangles ΔADB and ΔADC Both are right angle, â ABD= â ACD=90 degree They have congruent acute angle â BAD and â CAD( since AD is angle bisector) They share hypotenuse AD therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
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Write the square or cube for each number.
IRISSAK [1]

Answer:

1) 19³=6859

2) 16² =256

3) 15³ =3375

4) 20² =400

5) 10³ =1000

Step-by-step explanation:

using your calculator to (square = number times itself) or (cube = number times itself times itself again)

4 0
2 years ago
Three friends are training for a race. Last week, Jacquis ran 3 more miles than Ellen. Miryana ran 1.5 miles as far as Jacquis.
maks197457 [2]

ellen ran 2.5 miles last week

3 0
3 years ago
Read 2 more answers
Please answer quickly in those 3 question if u know one of those answer than answer it if u don't than its fine
inn [45]
Lst question:  x = 5, y = 7

2nd question: x = -1, y = 5

3rd question: x = 98, y = 80
3 0
3 years ago
Read 2 more answers
1. what’s the distance between (-8, -6) and (4, 10)?
charle [14.2K]

Use the formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(-8,\ -6),\ (4,\ 10)\\\\d=\sqrt{(4-(-8))^2+(10-(-6))^2}=\sqrt{12^2+16^2}\\\\=\sqrt{144+256}=\sqrt{400}=\boxed{20}\\\\(5,\ 14),\ (-3,\ -9)\\\\d=\sqrt{(-3-5)^2+(-9-14)^2}=\sqrt{(-8)^2+(-23)^2}\\\\=\sqrt{64+529}=\boxed{\sqrt{593}\approx24.35}

7 0
3 years ago
The point M(-6, -4) is translated 2 units right. What are the coordinates of the resulting point, M′?
fredd [130]
B) (-4, -4)

When moving to the right you are moving to a more POSITIVE region on the x-axis; meaning, the y-value (vertical axis) does not get affected unless you’re moving up or down.

Remember: (-6, -4)
X = -6
Y = -4

If you move 2 units to the right (x-axis) you go from -6 + 2 which equals -4. And again, you’re not moving up and down so your
y-value stays the same and your new coordinates are (-4, -4)
7 0
3 years ago
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