-4 to-6 is 2 left for x and 4 to -3 is 7 left so g is 2 left of -6 and 7 left of -3 = -8,-10
18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.
<u>Step-by-step explanation:</u>
Let x = kg of 15% copper alloy
Let y = kg of 60% copper alloy
Since we need to create 90 kg of alloy we know:
x + y = 90
51% of 90 kg = 45.9 kg of copper
So we're interested in creating 45.9 kg of copper
We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:
0.15x + 0.60y = 45.9
but
x + y = 90
x= 90 - y
substituting that value in for x
0.15(90 - y) + 0.60y = 45.9
13.5 - 0.15y + 0.60y = 45.9
0.45y = 32.4
y = 72
Substituting this y value to solve for x gives:
x + y = 90
x= 90-72
x=18
Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.
Answer:
It is either 11/12 or 0.91666666667.....
Step-by-step explanation:
Because this can not be actually divided into a "number" like 2 or 5, we can only get a approximate. Like the top answer.
Round to the nearest ten is 0.9
Round it to nearest hundredths is 0.92
The correct answer is C) 1/3 and (0, 1)
The y-intercept part is somewhat simple. In order for it to be a y-intercept, the x value of the ordered pair must be 0. That is only true in B and C, therefore they are the only possible answers.
To find the slope, we must choose two points on the line and use the slope formula. We can start by using the y-intercept (0, 1) and also (3, 2). Now we use the slope formula.
m = (y2 - y1)/(x2 - x1)
In this equation m is equal to slope, the first point is (x1, y1) and the second point is (x2, y2)
m = (y2 - y1)/(x2 - x1)
m = (2 - 1)/(3 - 0)
m = 1/3
Now knowing the slope, you can match this with answer C.
Answer:
The product 
Step-by-step explanation:
Given expression
and 
We have to find the product of 
Consider the given expression 
Multiply fractions, we have,


Cancel common factor ( b - 5 )
we have, 
Apply exponent rule,




Cancel common factor b , we have,

Thus, the product 