Mean=total/the number of values =>total=mean*the number of values
the total of the first set of 8 numbers is : total=8*8=64
the total of the second set of 12 numbers is: 12m
the total of the 20 numbers is: 64+12m
the mean of the 20 number is: (64+12m)/20=5
solve for m: 64+12m=100
12m=36
m=3
Fron the table given:
A3 = 112,
A8 = - 3,584
An = A1 *r ^ (n-1)
=> A3 = A1 (r^2) = 112
A8 = A1(r^7) = - 3,584
=> - 3584 / 112 = (r^7) / (r^2)
=> (r^5) = - 32
=> r = - 2
=> A1 (- 2)^2 = 112
=> A1 = 112 / 4 = 28
Answer: a1 = 28
Wait what?? If you are talking about how much it could have caught it's 0 I guess
First get y by its self , then graph , find intersection point and plug in x and y to both equations, see if it makes sense , then the solution must be you intersection point
Answer:
C
Step-by-step explanation:
Now there are 6+4+8+1+1=20 dads in the Dads Club.
Fewer than 3 children have
- 1 child - 6 dads
- 2 children - 4 dads.
So, 6+4=10 dads have fewer than 3 children.
The probability that the dad of Dads Club has fewer than 3 children is

The probability that the next dad to join Dads Club has fewer than 3 children is reasonable to be 50%.