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alisha [4.7K]
3 years ago
9

Yearly tuition, housing, and fees for a local college are $9500, $1500, and $1870 respectively. You have saved $6100 and have a

scholarship for $2500. How much more will you need for the first year?
$3030

$4270

$21,470

$16,470
Mathematics
2 answers:
DiKsa [7]3 years ago
7 0
The answer is $4270
add 9500+1500+1870=12870 then subtract your savings 12870-6100=6770 then subtract your scholarship 6770-2500=4270
romanna [79]3 years ago
3 0

The answer is $4,270. Hope I could help! :D

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Logan is going to invest in an account paying an interest rate of 3.1% compounded continuously. How much would Logan need to inv
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Answer:

yessir

Step-by-step explanation:

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Pls help me on this!
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It’s b :) haha i got it right
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2 years ago
The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

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3 years ago
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Emery bought 3 cans of beans that had a total weight of 2.4 pounds. If each can of beans weighed the same amount, which model co
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Answer:

  • y=0.8x
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Step-by-step explanation:

The 3 cans of beans had a total weight of 2.4 Pounds

Therefore:

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The following applies from the options.

  • y=0.8x where y is the weight and x is the number of cans.
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Using y=0.8x

When x=5, y=0.8 X 5=4

When x=15, y=0.8 X 15=12

When x=20, y=0.8 X 20=16

\left|\begin{array}{c|c}\text{Number of Cans,x}&\text{Total Weight (in Pounds),y}\\-------&--------\\5&4\\15&12\\20&16\end{array}\right|

  • On a coordinate plane, the x-axis is labeled number of cans and the y-axis is labeled total weight (in pounds. A line goes through points (5, 4) and (15, 12). This can be clearly seen from the table above as (5,4) and (15,12) are points on the line.
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How many leaves on a tree diagram are needed to represent all possible combinations tossing a coin 3 times?
Anika [276]
N = 3 is the number of times the coin is tossed. Since there are 2 outcomes per toss, this means that there are 2^n = 2^3 = 2*2*2 = 8 outcomes total. Therefore, there are 8 leaves total. 

If we make
H = heads
T = tails

Then here are the 8 outcomes in the sample space
HHH
HHT
HTH
THH
HTT
THT
TTH
TTT


8 0
3 years ago
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