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sattari [20]
3 years ago
12

What is the height of a triangle whose base is 8.6 centimeters and whose area is 79.12 square centimeters? round to the nearest

tenth
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

height = 18.4 cm

Step-by-step explanation:

A = (1/2)*b*h

A = 79.12 sq. cm = (1/2)* 8.6  *  h

A = 79.12 sq. cm = 4.3  *  h

h = 79.12 / 4.3  =  18.4 cm

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in triangle ABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. Find the perimeter o
alexdok [17]

35

since m and n are the midpoints of ab and ac resistively

then ,bc=2mn=16

since m and l are the midpoints of ba and bc respectively

then, ac =2mn =10

then,nc =1/2 × 10 =5

similary, mb=6

then ,perimeter=nc+mb+mn+bc=5+6+8+16=35

6 0
3 years ago
Helllllllllllilllllyyeneyneyn
Deffense [45]

Answer:

b

Step-by-step explanation:

6 0
2 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
2 years ago
In the following questions, look at different ways to represent the relation given by the equation y = x2 - 1. The table below s
Nady [450]

Answer:

a= 3

b= 0

Step-by-step explanation:

4 0
2 years ago
Each carton of eggs cost $3 make a table and an equation
dolphi86 [110]

Answer:

y = 3x

Step-by-step explanation:

x is number of cartons of eggs

y is cost

cost increases by 3 for every carton of eggs, so slope is 3

x and y intercepts are zero because there is no cost when there are no eggs

equation: y = 3x

7 0
3 years ago
Read 2 more answers
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