|
|__x_- 4___________ 2x³/2x² =x
2x² + 2x +3 | 2x³ - 6x² +7x +3
- (<span>2x³ +2x² +3x)
</span> -8x² +4x +3 -8x²/2x² = -4
<span>-(-8x² -8x -12)
</span> 12x +15
(x-4) + (12x +15)/(2x² + 2x +3)
Answer:
ma'am or sir... there is no picture attached... but whats the question?
Step-by-step explanation:
There are 9 trucks and 15 cars
If it’s a slope- intercept form/ y=mx+b then it’s y=1x+0 because each time it goes up one and over one which is 1/1 or 1 whole and the y-intercept is at (3,0) and we use the Y which is 0
Answer:
y=7x+3
Step-by-step explanation:
Hi there!
We are given the equation y=7x-5 and we want to find the equation of the line that is parallel to it, and contains the point (4,31)
First, let's find the slope of y=7x-5, since parallel lines have the same slopes
The line y=7x-5 is written slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since 7 is in the place of where m is, the slope of the line is 7
It's also the slope of the line parallel to it.
We can substitute 7 as m into the formula y=mx+b for our new line:
y=7x+b
Now we need to find b
Since the equation will pass through the point (4, 31), we can use it to solve for b; substitute 31 as y and 4 as x
31=7(4)+b
Multiply
31=28+b
Subtract 28 from both sides
3=b
Substitute 3 as b
y=7x+3
Hope this helps!
