What is the area of a parallelogram with a base of 5, another base of 4.56 units. and i height of 2.

A transformation T : (x, y) → (x + 3, y + 1). Find the preimage of the point (4, 3) under the given transformation. (7, 4) (1, 2

motikmotik

Answer:

(1, 2)

Step-by-step explanation:

Remember that the final shape and position of a figure after a transformation is called the image, and the original shape and position of the figure is the pre-image.

In our case, our figure is just a point. We know that after the transformation T : (x, y) → (x + 3, y + 1), our image has coordinates (4, 3).

The transformation rule T : (x, y) → (x + 3, y + 1) means that we add 3 to the x-coordinate and add 1 to the y-coordinate of our pre-image. Now to find the pre-image of our point, we just need to reverse those operations; in other words, we will subtract 3 from the x-coordinate and subtract 1 from the y-coordinate.

So, our rule to find the pre-image of the point (4, 3) is:

T : (x, y) → (x - 3, y - 1)

We know that the x-coordinate of our image is 4 and its y-coordinate is 3.

Replacing values:

(4 - 3, 3 - 1)

(1, 2)

We can conclude that our pre-image is the point (1, 2).

6 0

3 years ago

Identify the initial amount a and the growth factor b in the exponential function.f(t)=1.4^t

vaieri [72.5K]

Initial amount is when no change has happened or when t=0
that iniital amoun tis 1
the growth factor
welll, it grows by 40% each time of previous times

I would say growth factor of 1.4

f(x)=a(b)^t
f(t)=1(1.4)^t
initial amount is 1
grouth factor is 1.4

6 0

3 years ago

Can someone help me with this question: What is the 40th term of these sequences below. 13, 26, 39, 52,...... 6, 12, 18, 24,....

Nina [5.8K]

Answer:520; 240

Step-by-step explanation:

a. 13, 26, 39, 52,......

a = First term = 13

d = common difference = 26 - 13 = 13

40th term = a + (n - 1)d = a + (40-1)d = a + 39d

= 13 + (39 × 13)

= 13 + 507