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Anuta_ua [19.1K]
3 years ago
8

9) Is 0 a solution to 3x + 8 = 5x + 8? Explain or show your reasoning .​

Mathematics
2 answers:
Vsevolod [243]3 years ago
7 0

Answer: yes

Explanation: To decide whether 0 is a solution for

this equation, we can simply plug a 0 in for x.

If the statement holds true, then 0 is a solution.

Plugging in 0 for x, we have 3(0) + 8 = 5(0) + 8.

Now since anything times 0 is 0, we have 8 = 8.

Since 8 = 8 is a true statement, 0 is a solution.

alex41 [277]3 years ago
4 0

Answer:

x=0, yes.

Step-by-step explanation:

3x+8=5x+8

5x-3x+8=8

2x+8=8

2x=8-8

2x=0

x=0/2

x=0

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A polynomial is the sum of at least one term. For example, x^3+1 is a polynomial. A monomial is a polynomial with only one term, such as 2x^2. A binomial is a polynomial with two terms, and a trinomial is one with three terms. The example you gave is a trinomial (which is also a polynomial). Degree of a polynomial is the largest sum of variable powers in any term of the polynomial. So, for example, x^2 y has degree 3, and x^3+x^2 also has degree 3. A sixth degree polynomial would be x^6-2x+1, for example.
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A scientist needs to make 2 liters of saline solution (salt water), in which the salt
gulaghasi [49]

Answer:

1.60 L of 10% solution

0.40 L of 35% solution

Step-by-step explanation:

If x = amount of 10% saline solution, and y = amount of 35% saline solution, then:

x + y = 2

0.10x + 0.35y = 0.15(2)

Solve with substitution:

0.10x + 0.35(2 − x) = 0.15(2)

0.10x + 0.70 − 0.35x = 0.30

0.40 = 0.25x

x = 1.60

y = 0.40

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3 years ago
The equations y = tan^2 (x) and y = 1 are graphed below. According to the graphwhich of the following is part the solution to th
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What is the percentage for 64 of 300
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3 0
3 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
3 years ago
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