A publisher prints 1,512 copies of a book in each print run. If they print 305 runs, how many books will be printed?
2 answers:
Answer:
Step-by-step explanation:
According to the exercise, the number of copies of a book printed in each run is:
Then, let be "x" the number of the number of books that will be printed in 305 runs.
In order to calculate the value of "x", you must multiply 1,512 (which is the number of copies of a book printed in each print run) by 305.
Therefore, you get that the number of books that will printed in 305 runs is:
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Answer:
- g(20) > f(20)
- g(x) exceeds f(x) for any x > 4
Step-by-step explanation:
As with most graphing problems not involving straight lines, it works well to start with a table of values. Pick a few values of x and compute f(x) and g(x) for those values. Plot the points and draw a smooth curve through them.
As in the attached, your table will show that there are two points of intersection between f(x) and g(x), and that for values of x more than 4, g(x) becomes much greater very quickly. Both curves rapidly reach the top of your graph space.
To find whether f(20) or g(20) is greater, you can evaluate the functions for that value of x.
f(20) = 20² = 400
g(20) = 2²⁰ = 1,048,576
Clearly, g(20) has a greater value.
Answer:
Step-by-step explanation:
<u>Given Second-Order Homogenous Differential Equation</u>
<u>Use Auxiliary Equation</u>
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<u>General Solution</u>
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Note that the DE has two distinct complex solutions where
and
are arbitrary constants.