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3 years ago

What is the slope of this table

Mathematics

2 answers:

Elden [556K]3 years ago

6 0

Answer:

Step-by-step explanation:

slope = (y2-y0)/(x2-x0)

Using pts (-4,-9), (3,12):

(12-(-9))/(3-(-4))= 21/7 = 3

rodikova [14]3 years ago

5 0

3x

What equation: y= 3x+3

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What does 9/5 equals to ?

goldenfox [79]

Answer:

9/5 = 1.8

All you have to do is divide the numerator by the denominator.

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-Mikayla

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3 years ago

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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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2 years ago

If a car is traveling at 65 miles per hour, then how far does it travel in 2 hours?

frez [133]

65 miles per hour means that for each hour, it goes 65 miles

65 miles*2 hours= 130 miles

Final answer: 130 miles

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3 years ago

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mr_godi [17]

Answer:

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3 years ago

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Marrrta [24]

Answer:

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