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-BARSIC- [3]
3 years ago
12

Hrs

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0
10 because is the total hours was spent walking
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Write a real-world problem involving a percent that can be solved by using the proportion 3/b= 60/100. Then solve the proportion
inessss [21]
Dax goes to the store to buy milk. There is a sale for milk, and it now costs 3 dollars since it was 60% off. What was the original price of the milk?
3 - 60
x - 100
Cross multiply
300=60x
5=x

The milk original cost 5 dollars.
8 0
3 years ago
There are 8 students on the minibus. Five of the students or boys. What fraction of the students are boys
blagie [28]
The fraction would be 5/8
3 0
3 years ago
How many different arrangements of 5 letters can be made from the 26 letters of the alphabet?
VikaD [51]
Answer: P(26,5).

That is all the possible combinations of 5 letters made out from 26 letters.

That is 26! / [ 5! ( 26 - 5)! ] = 26! / [5! 21! ] = 26*25*24*23*22*21! / [ 5! 21!] =

= 26*25*24*23*22 / [5*4*3*2*1] = 65,780 arrangements.


5 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
A members-only speaker series allows people to join for $28 and then pay $4 for every event attended. What is the total cost for
wariber [46]

Given:

Joining fee = $28

Fee of each event = $4

To find:

Total cost for someone to attend 4 events.

Solution:

Let the number of events be x and total fee be y.

Fee for 1 event = $4

Fee for x events = $4x

Joining fee remains constant. So, the total fee is

y=28+4x

Substitute x=4 in this equation.

y=28+4(4)

y=28+16

y=44

Therefore, total cost of 4 events is $44.

8 0
3 years ago
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