Answer:
1/ 6^12
Step-by-step explanation:
f[x} = x ^ (-2x)
f(6) = 6 ^ (-2*6)
= 6 ^ -12
We know the negative exponent moves it to the denominator
= 1/ 6^12
Integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2
Answer:
Simplifying
4cos(10x) + 2 = 2
Remove parenthesis around (10x)
4cos * 10x + 2 = 2
Reorder the terms for easier multiplication:
4 * 10cos * x + 2 = 2
Multiply 4 * 10
40cos * x + 2 = 2
Multiply cos * x
40cosx + 2 = 2
Reorder the terms:
2 + 40cosx = 2
Add '-2' to each side of the equation.
2 + -2 + 40cosx = 2 + -2
Combine like terms: 2 + -2 = 0
0 + 40cosx = 2 + -2
40cosx = 2 + -2
Combine like terms: 2 + -2 = 0
40cosx = 0
Solving
40cosx = 0
Solving for variable 'c'.
Move all terms containing c to the left, all other terms to the right.
Divide each side by '40'.
cosx = 0.0
Simplifying
cosx = 0.0
The solution to this equation could not be determined.
Step-by-step explanation:
Answer:
7
Step-by-step explanation: