Find the total area for the regular pyramid T.A. =
1 answer:
Answer:
The answer to your question is At = 48 + 36
Step-by-step explanation:
Area = Area of the base + Lateral area
a) Area of the base
Area = length x height / 2
length = 12
height² = 12² - 6²
= 144 - 36
= 108
height = = 6
Area = 12 x 6
= 36
b) Lateral area
height² = 10² - 6²
= 100 - 36
= 64
height = 8
Area = 12 x 8/2
= 48
c) Total area
At = 48 + 36
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Same as before, if we take 368 to be the 100%, how much is 20% off that?
so, the discount is that much, thus, the discounted price is then 368 - d.
so, the discount is that much, thus, the discounted price is then 368 - d.
Hello from MrBillDoesMath!
Answer:
Perimeter = 60
Height = 18/5
Discussion:
The diagonals of a rhombus bisect each other at right angles. So a rhombus can be viewed as the union of 4 congruent right triangles, each with legs (1/2)*18 = 9 and (1/2) *24 = 12. See attachment. This gives a hypotenuse length of 15 so the Perimeter = 4 *c = 60.
The height ( = altitude) of a rhombus is
= area / length of base
= (1/2) ( (18) * 24) /c
= (1/2) ( 18 * 24) / 60
= 18/5
Thank you,
MrB
