2x^2 + 7x + 3 ; you multiple each the terms in the first set or parentheses by the other
Answer:
C. All real numbers except 3/4
Step-by-step explanation:
We are given


Firstly, we will find f/g

Domain:
We know that domain is all possible values of x for which any function is defined
so, we know that denominator of any function can not be zero
so, firstly we set denominator =0
and then we can solve for x

Add both sides by 3



so, this function is defined for all values of x except at

Domain will be
All real numbers except 3/4
Answer:
x(6 + 15y)
Step-by-step explanation:
In this instance, you can divide by a factor of x.
6x/x = 6
15xy/x = 15y
Therefore, we are left with 6 + 15y.
Answer:
(ab - 6)(2ab + 5)
Step-by-step explanation:
Assuming you require the expression factorised.
2a²b² - 7ab - 30
Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term
product = 2 × - 30 = - 60 and sum = - 7
The factors are - 12 and + 5
Use these factors to split the ab- term
= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )
= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term
= (ab - 6)(2ab + 5) ← in factored form
Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.
For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

In this problem:
- 95% pass final inspection, hence

- 120 components are inspected in one day, hence
.
The variance is given by:

The variance of the number that pass inspection in one day is 5.7.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377