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meriva
3 years ago
8

Which of these statements is not one of Euclid axioms

Mathematics
2 answers:
earnstyle [38]3 years ago
8 0

Answer:

Things which are equal to the same thing are also equal to one another. If equals be added to equals, the wholes are equal. If equals be subtracted from equals, the remainders are equal. Things which coincide with one another are equal to one another.

lorasvet [3.4K]3 years ago
6 0
They are a equally big fan of the best way out here and the cashapp method of a and a full of flavor that shi was the best way we could have seen in a while and it is
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Math help ✄✐
brilliants [131]

D) as age increases, weight increases by 5

4 0
3 years ago
Triangle P Q R is shown. Angle Q P R is a right angle. The length of Q P is 8 StartRoot 3 EndRoot and the length of P R is 8.
Vika [28.1K]

Answer: Length of side QR is 16 units.

Step-by-step explanation: Given that dimensions of  PQR

QPR= 90degrees

6 0
2 years ago
A coyote had 10 pups in her third litter. It was twice as many as in her second litter, her second litter, and her second litter
Yuki888 [10]
A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter

her second litter had 3 more pups than her first.( first litter +3)=2nd litter

Find the number of pups in her litter

6 0
3 years ago
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
The base of a triangle is 8 1 3 meters and the height of the triangle is the fourth root of 16 meters meters. What is the area o
just olya [345]

Answer:

The area of triangle is 8 \frac{1}{3}\ m^{2}

Step-by-step explanation:

we know that

The area of a triangle is equal to

A=(1/2)bh

we have

b=8 1/3 m

convert to an improper fraction

8 1/3 m=(8*3+1)/3=25/3 m

The fourth root of 16 is equal to 2

\sqrt[4]{16}=(2^{4})^{1/4}=2

so

h=2 m

substitute

A=(1/2)(25/3)2=25/3\ m^{2}

convert to mixed number

25/3=(24/3)+(1/3)=8+1/3=8 \frac{1}{3}\ m^{2}

5 0
3 years ago
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