Pythagorean Theorem: a^2+b^2=c^2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
b = 21.2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
b = 21.2
A 2×2 square is centered at the origin. It is dilated by factor of 3. What are coordinates of the vertices of the square?
1 answer:
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THE CORRECT OPTIONS ARE
B
C
E
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