A dilation with a scale factor of 4 is applied to the three line segments shown. The resulting images are P'Q', A'B', and M'N' D
rag and drop the measures to correctly match the lengths of the images. 1 P'Q A'B' M'N
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now, if we just knew what g(2) is, we'd be golden, however, we dunno
BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)
for inverse expressions, the domain and range is the same as the original, just switched over
so, g(2) = some range value
that means if we use that value in f(x), f( some range value) = 2
so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2
thus 2 = 2x+sin(x)
hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
