The sides of a triangle must satisfy the triangle inequality, which states the sum of the lengths of any two sides is strictly greater than the length of the remaining side.
We really only have to check if the sum of the two smaller sides exceeds the largest side.
A. 5+6>7, ok
B. 6+6>10, ok
C. 7+7=14 Not ok, this is a degenerate triangle not a real triangle
D. 4+6>8 ok
Answer: C
Answer:
OPTION D
Step-by-step explanation:
We have to determine which option determines the function given above.
To determine the function, just substitute the values and compare LHS and RHS.
we have 



Here,
is the domain and
is the co-doamin.
Therefore, 
Now, OPTION A: 
Substitute x = 4. We get f(x) = 3
18.
So, OPTION A is rejected.
Similarly, OPTION B: 
Substitute x = 4. We get f(4) = 22
18.
It is rejected as well.
Now, for OPTION C: 
Substitute x = 4. We get f(4) = -3
18.
So, OPTION C is also rejected.
OPTION D: 
Substitute x = 4. We get f(4) = 18.
Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.
Answer:
option 2
Step-by-step explanation:
Answer:
MN = 68
Step-by-step explanation:
LN = 91
LM = 23
Points L, M, and N are collinear, therefore, according to the segment addition postulate, the following can be deduced:
LM + MN = LN
23 + MN = 91 (Substitution)
Subtract 23 from both sides
23 + MN - 23 = 91 - 23
MN = 68
Y intercept is found by having the x value equal 0 (and vise versus for x intercept) so 5y=10 or simplified y=2
Then you have to find the x intercept (2x=10 and or x=5) then it’s just run over rise (2/5)