Cos θ = adjacent / hypothenus = 5/13
opposite = sqrt(hypothenus^2 - adjacent^2) = sqrt(13^2 - 5^2) = sqrt(169 - 25) = sqrt(144) = 12
sec θ = 1/cos θ = 1/(adjacent / hypothenus) = hypothenus / adjacent = 13/5
cot θ = 1/tan θ = 1/(opposite/adjacent) = adjacent / opposite = 5/12
sec θ = 13/5
cot θ = 5/12
Answer:
A) the unknown is 5
B) the unknown is also 5
C) unknown is 23
D) unknown is 19
Step-by-step explanation:
Hope this is right and helps!
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➷ As you can tell, the ratio of the lengths is 2 : 1 (the length of a is twice the length of b)
The ratio for area would be the squared version of the length ratio
2^2 = 4
1^1 = 1
The ratio for area is 4 : 1
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Answer:
Cathode Ray tube is the answer I think
Answer:
32.33 <= m
Step-by-step explanation:
Since we are dealing with below sea level our initial starting point and max level will both be negative values, while our descending rate will also be negative because we are going down. Using the values provided we can create the following inequality...
-400 <= -12m - 12
Now we can solve the inequality to find the max number of minutes that the submarine can descend.
-400 <= -12m - 12 ... add 12 on both sides
-388 <= -12m ... divide both sides by -12
32.33 <= m
