How do you find the r?

You flip 3 coins. Is the probability of obtaining 2 heads and 1 tail in any order the same as the probability of obtaining a hea

konstantin123 [22]

Answer:

the probability of obtaining 2 heads and 1 tail in any order is higher than the probability of obtaining a head, than a head then a tail

Step-by-step explanation:

since the probability (p) of obtaining 2 head and 1 tail in any order is

P1 = p of obtaining ( H , H ,T) + p of obtaining ( H , T ,H ) + p of obtaining ( T , H ,H ) = 3*p of obtaining ( H , T ,H)

assuming a fair coin then p heads = p tails = 0.5

thus since each flip is independent from the others

p( H , H ,T)=p( H , T ,H )= p( T , H ,H )= P=0.5*0.5*0.5= 1/8

thus P1 =3*1/8=3/8

while the probability of obtaining a head, than a head then a tail is

P2= p of obtaining ( H , T ,H)= 1/8

then P1=3/8 >P2=1(8

therefore the probability of obtaining 2 heads and 1 tail in any order is higher than the probability of obtaining a head, than a head then a tail

6 0

3 years ago

If you flip a fair coin 7 times, what is the probability that you will get exactly 4 tails?

andre [41]

Probability that you will get exactly 4 tails, if you flip a fair coin 7 times is: $\frac{35}{128}$

Step-by-step explanation:

We need to find the probability that you will get exactly 4 tails, if you flip a fair coin 7 times.

This is the combination question.

The total combinations will be: 2^7=128

Now, finding number of ways we can get exactly 4 tiles:

We will use the formula:

$^nC_k=\frac{n!}{k!(n-k)!}$

in our given question, n= 7, k= 4

Putting values:

$^nC_k=\frac{n!}{k!(n-k)!}\\^7C_4=\frac{7!}{4!*3!}\\ ^7C_4=\frac{7*6*5*4!}{4!*3!}\\ ^7C_4=\frac{7*6*5}{6}\\ ^7C_4=35$

So, Probability that you will get exactly 4 tails, if you flip a fair coin 7 times is: $\frac{35}{128}$

Keywords: Probability

Learn more about Probability at:

#learnwithBrainly

7 0

3 years ago

What the answer to this?

garik1379 [7]

Answer:

Step-by-step explanation:

$9-5\div (8-3)\times 2+6\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(8-3\right)\::\quad 5\\=9-5\div \:5\times \:2+6\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:5\div \:5\times \:2\::\quad 2\\=9-2+6\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:9-2+6\:\\:\quad 13$

7 0

3 years ago

The right expression to calculate how much money will be in an investment account 14 years from now if you deposit $5,000 now an

Svet_ta [14]

Answer:

The expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

Step-by-step explanation:

The formula to compute the future value is:

$FV=PV[1+\frac{r}{100}]^{n}$

PV = Present value

r = interest rate

n = number of periods.

It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.

The expression to compute the amount in the investment account after 14 years is,

$FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}$