Question

(3x^2+3)+(3x^2+x+4)?

Answer 1

Answer:

6x^2+x+7

Step-by-step explanation:

(3x^2+3)+(3x^2+x+4)

6x^2+3+x+4

6x^2+x+7

Answer 2

You first start with adding the number in the parentheses,because none of them can add in this equation it stays the same:

(3x^2 + 3) + (3x ^2 + x + 4)

Since there is nothing that we can do while there are parenthaseese we remove them:

3x^2 + 3 + 3x ^2 + x + 4

Next add the x^2’s:

6x^2 + 3 + x + 4

Lastly the normal numbers:

6x^2 + 7 + x

Now that there are no more numbers that are the same, 6x^2 + x + 7 is your simplified equasion.

Hope this helps! :)