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3 years ago

10

(3x^2+3)+(3x^2+x+4)?

2 answers:

OverLord2011 [107]3 years ago

8 0

Answer:

6x^2+x+7

Step-by-step explanation:

(3x^2+3)+(3x^2+x+4)

6x^2+3+x+4

6x^2+x+7

Alex777 [14]3 years ago

3 0

You first start with adding the number in the parentheses,because none of them can add in this equation it stays the same:

(3x^2 + 3) + (3x ^2 + x + 4)

Since there is nothing that we can do while there are parenthaseese we remove them:

3x^2 + 3 + 3x ^2 + x + 4

Next add the x^2’s:

6x^2 + 3 + x + 4

Lastly the normal numbers:

6x^2 + 7 + x

Now that there are no more numbers that are the same, 6x^2 + x + 7 is your simplified equasion.

Hope this helps! :)

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3 years ago

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Find the value of x for which ABCD must be a parallelogram

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They are equal so...

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3 years ago

Tell me which option is correct: (0,m) (b,0) (m,0) (0,b) which one of those

strojnjashka [21]

Answer:

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Search for questions & chapters

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Class 11

>>Physics

>>Units and Measurement

>>Errors in Measurement

>>You measure two quantities ...

Question

Bookmark

You measure two quantities as A=1.0m±0.2m, B=2.0m±0.2m. We should report correct value for

AB

as

Medium

Solution

verified

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Correct option is

D

1.4m±0.2m

Here, A=1.0m±0.2m, B=2.0m±0.2m

AB=(1.0m)(2.0m)=2.0m

2

AB

=

2.0m

=1.414m

Rounding off to two significant figures, we get

AB

=1.4m

AB

ΔAB

=

2

1

(

A

ΔA

+

B

ΔB

)=

2

1

(

1.0

0.2

+

2.0

0.2

)=

2

0.3

Δ

AB

=

2

0.3

×

AB

=

2

0.3

×1.414=0.212m

Rounding off to one significant figure, we get

Δ

AB

=0.2m

The correct value for

AB

is 1.4m±0.2m

8 0

3 years ago

Juans three math quizzes this week took him 1/3?4/6?and1/5 hour to complete. List all the fraction from least to greatest

Alex

Answer:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

Step-by-step explanation:

Given fractions $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We need to list them from least to greatest.

In order to arrange them from least to greatest, we need to find the least common denominator of $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We have 3, 6 and 5 in denominators.

Least common multiple of 3, 6 and 5 is = 30, because 30 is least number that can be divided by all three number 3, 6 and 5.

Let us covert each denominator as 30.

Multiplying first fraction $\frac{1}{3}$ by 10 in top and bottom, we get

$\frac{1}{3} = \frac{1\times10}{3\times10}=\frac{10}{30}$

Multiplying first fraction $\frac{4}{6}$ by 5 in top and bottom, we get

$\frac{4}{6} = \frac{4\times5}{6\times5}=\frac{20}{30}$

Multiplying first fraction $\frac{1}{5}$ by 6 in top and bottom, we get

$\frac{1}{5} = \frac{1\times6}{5\times6}=\frac{6}{30}.$

Now, we can check $\frac{10}{30}, \frac{20}{30} \ and \ \frac{6}{30}.$

$\frac{6}{30}$ is the smallest, $\frac{10}{30}$ is greater and $\frac{20}{30}$ is the greatest.

Therefore, we can arrange fractions $\frac{6}{30}, \frac{10}{30} \ and \ \frac{20}{30}.$

Writing original fractions in place of equivalent fractions, we can write

$\frac{1}{5}$ , $\frac{1}{3}$ and $\frac{4}{6}$ .

Therefore, the order the amounts of paint from least to greatest is:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

4 0

3 years ago

What’s the answer to this equation?

Tresset [83]

Answer:

Part A) The graph in the attached figure

Part B) see the explanation

Step-by-step explanation:

Part A) Graph the function

we have the quadratic function

$y=3x^2-12x-36$

This is a vertical parabola open upward

The vertex is a minimum

using a graphing tool

The graph in the attached figure

Part B) What are the values of a, b and c?

we know that

The values of a and b represent the x-intercepts of the quadratic equation

The x-intercepts are

(-2,0) and (6,0)

so

$a=-2\\b=6$

Find the value of c

we know that

The x-coordinate of the vertex in a vertical parabola is equal to the midpoint of the roots

so

The value of c is equal to

$c=\frac{a+b}{2}$

substitute the given values

$c=\frac{-2+6}{2}=2$

see the attached figure

7 0

3 years ago