A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
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People were in favor of the new hotel=25% of 6000 people.
25% of 6000 people=(25/100)*6000=(25*6000)/100=1500 pople.
1500 people were in favor of the new hotel.
The solutions of the equation are -12 and 16
Step-by-step explanation:
Absolute value describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The absolute value of a number is never negative, if IxI = a, where a > 0, then
∵ 2Ix - 2I - 8 = 20
- At first add 8 to both sides
∴ 2Ix - 2I = 28
- Then divide both sides by 2
∴ Ix - 2I = 14
Now By using the notes above equate x - 2 by 14 and -14
∵ x - 2 = 14
- Add 2 to both sides
∴ x = 16
∵ x - 2 = -14
- Add 2 to both sides
∴ x = -12
The solutions of the equation are -12 and 16
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X(u, v) = (2(v - c) / (d - c) + 1)cos(pi * (u - a) / (2b - 2a))
y(u, v) = (2(v - c) / (d - c) + 1)sin(pi * (u - a) / (2b - 2a))
As
v ranges from c to d, 2(v - c) / (d - c) + 1 will range from 1 to 3,
which is the perfect range for the radius. As u ranges from a to b, pi *
(u - a) / (2b - 2a) will range from 0 to pi/2, which is the perfect
range for the angle. So, this maps the rectangle to R.
Answer:
Step-by-step explanation:
hello :
if : r the radius ( r ≠0)
the circumference is : 2πr
the area is : πr²
so : πr² = 2πr
simplify by : r π you have : r=2
