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astraxan [27]
3 years ago
12

Y(x - (9 – 4y)); use x = 4, and y = 2

Mathematics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

6

Step-by-step explanation:

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Mafalda has a save percentage of 0.7380.7380, point, 738 so far this hockey season. Last season, her save percentage was 0.5850.
Snowcat [4.5K]

Answer:

0.153

Step-by-step explanation:

We have been given that Mafalda has a save percentage of 0.738 so far this hockey season. Last season, her save percentage was 0.585.

To find improvement in Mafalda's save percentage we will subtract last season's save percentage from this season's save percentage.

0.738-0.585=0.153

Therefore, Mafalda's save percentage improved by 0.153.

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3 years ago
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Find the altitude of a cylinder with with a radius of 9 and a surface area of approximately 791.68 units2.
Vika [28.1K]

In this question , it is given that we have a cylinder with with a radius of 9 and a surface area of approximately 791.68 units square.

The formula of surface area of cylinder is

A= 2 \pi r^2 + 2 \pi r h

Substituting the values of A and r, we will get

791.68 = 2* \pi * 9^2  + 2 * \pi * 9*h
\\
791.68 = 162 \pi + 18 \pi h
\\
791.68 -162 \pi = 18 \pi h
\\
h = \frac{791.68 -162 \pi}{18 \pi}
\\
h =5 units

So the height of the cylinder is 5 units .


4 0
3 years ago
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
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