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astraxan [27]
3 years ago
12

Y(x - (9 – 4y)); use x = 4, and y = 2

Mathematics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

6

Step-by-step explanation:

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What is two thousand,six hundred two in expanded form?
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2000 + 600+ 2

Step-by-step explanation:

expanded form is: way to write a number by adding the value of its digits

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If the dimension increased by doubled, tripled or quadrupled, then it will be 2x, 3x, or 4x for each dimension.

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Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).
ale4655 [162]

Answer:

The required equation is:

y = -\frac{3}{2}x+9

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)

We will find the slope of given line segment first

m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}

Let m_1 be the slope of perpendicular bisector then,

m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}

Now the mid-point

(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

y = m_1x+b

Putting the value of slope

y= -\frac{3}{2}x+b

Putting the point (2,6) to find the y-intercept

6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9

The equation is:

y = -\frac{3}{2}x+9

7 0
2 years ago
What is the area of the figure below ?
Airida [17]

Answer:

Step-by-step explanation:

Area of the figure = area of the down triangle + area of trapezium + area of the upper triangle

Down triangle:

Base b = 8 in

Height = 6 in

Area = \frac{1}{2}bh\\=\frac{1}{2}*8*6\\\\=4*6

= 24 in²

Trapezium:

bases a = 4 in & b = 6 in

Height h =  5 in

Area=\frac{(a+b)h}{2}\\\\=\frac{(4+6)*5}{2}\\\\=\frac{10*5}{2}\\\\=5*5

= 25 in²

Area of the upper triangle:

Base b = 6 in

Height = (8 - 5) = 3 in

Area=\frac{1}{2}bh\\\\=\frac{1}{2}*6*3\\\\=3*3

= 9 in²

Area of the figure = 24 + 25 + 9 = 58 in²

3 0
2 years ago
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