<span>There are 1 billion 9 digit numbers (000,000,000 through 999,999,999). There are 45 different combinations of two different numerals (10 x 9 divided by 2). There are 512 (2 to the 9th power) different permutations for any two numbers to be used in a 9 digit number</span>
Answer:
The vertex is the point (-6,-34)
Step-by-step explanation:
we know that
The equation of a vertical parabola into vertex form is equal to
where
(h,k) is the vertex of the parabola
In this problem we have
Convert in vertex form
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Complete the square . Remember to balance the equation by adding the same constants to each side.
Rewrite as perfect squares
The vertex is the point (-6,-34)
Fill in each slot in the square with variables <em>a</em>, <em>b</em>, <em>c</em>, <em>d</em>, and <em>e</em>, in order from left-to-right, top-to-bottom. In a magic square, the sums across rows, columns, and diagonals all add up to the same number called the <em>magic sum</em>.
The magic sum is -3.9, since "diagonal 2" (bottom left to top right) has all the information we need:
3 + (-1.3) + (-5.6) = -3.9
Use this to find the remaining elements
<em>a</em> + <em>b</em> + (-5.6) = -3.9
<em>c</em> + (-1.3) + <em>d</em> = -3.9
3 + <em>e</em> + 0.02 = -3.9
<em>a</em> + <em>c</em> + 3 = -3.9
<em>b</em> + (-1.3) + <em>e</em> = -3.9
(-5.6) + <em>d</em> + 0.02 = -3.9
- diagonal 1 (top left to bottom right):
<em>a</em> + (-1.3) + 0.02 = -3.9
You will find
<em>a</em> = -2.62
<em>b</em> = 4.32
<em>c</em> = -4.28
<em>d</em> = 1.68
<em>e</em> = -6.92
