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Makovka662 [10]
2 years ago
7

Luca solved an equation as shown, and verified

Mathematics
1 answer:
OLga [1]2 years ago
5 0

Answer:

3

Step-by-step explanation:

squaring both sides first gives 2x-5=x-3+1 hence simplifying further give x=3

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Complete each statement in the steps to solve x2 – 4x + 3 = 0 using the process of completing the square.
My name is Ann [436]
(x - 3)(x - 1)

x = 3 
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3 years ago
Write the following 12.5% as a fraction
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1/8 is a fraction to represent 12.5%

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Round to the nearest thousands<br> 3475.6993
Andreyy89

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3 years ago
Solve the system using elimination.<br> 2x + 18y = -9<br> 4x + 18y = -27
Elan Coil [88]

First, let's cancel out the x by multiplying 2x + 18y = -9 by -2.

-2 ( 2x + 18y = -9) = -4x -36y = 18

Then, we combine the two equations.

-4x + 4x = 0

18y - 36y = -18y

-27 + 18 = -9

Our new equation is -18y = -9.

Now, divide both sides by -18.

-18y / -18 = y

-9/ -18 = 1/2

y = 1/2

We can plug in a value for y since y = 1/2 now.

Let's use 2x + 18y = -9

Plug in y.

2x + 18(1/2) = -9

2x + 9 = -9

Then, subtract 9 from both sides.

2x = -18

Divide by 2.

2x/2 = x

-18/2 = -9

x = -9

Lastly, we can plug in both x and y values to see it works.

2(-9) + 18(1/2) = -9

-18 + 9 = -9

Therefore, the values of x and y does work.

x = -9

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4 0
3 years ago
Suppose that 2 ≤ f '(x) ≤ 4 for all values of x. What are the minimum and maximum possible values of
Vesna [10]

Answer:

Step-by-step explanation:

By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that

f'(c) = [f(6) - f(1)]/ (6 - 1)

So, f(6) - f(1) = 5f'(c).

Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20

So, f(6) - f(1) is between 10 and 20.  

5 0
2 years ago
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