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Ganezh [65]
3 years ago
8

In the parabola y = (x + 12 + 2, what is the vertex?

Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

The vertex is the point (-6,-34)

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

In this problem we have

y=x^{2}+12x+2

Convert in vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-2=x^{2}+12x

Complete the square . Remember to balance the equation by adding the same constants to each side.

y-2+36=x^{2}+12x+36

y+34=x^{2}+12x+36

Rewrite as perfect squares

y+34=(x+6)^{2}

y=(x+6)^{2}-34

The vertex is the point (-6,-34)

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Answer:

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3 years ago
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nasty-shy [4]

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2 years ago
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Determine an appropriate domain of the function. Identify the independent and dependent variables. A stone is thrown vertically
Artemon [7]

Answer:

the domain of the function = [0,12]

Step-by-step explanation:

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6 0
3 years ago
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