Question

In the parabola y = (x + 12 + 2, what is the vertex?

Answer 1

Answer:

The vertex is the point (-6,-34)

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

In this problem we have

$y=x^{2}+12x+2$

Convert in vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2=x^{2}+12x$

Complete the square . Remember to balance the equation by adding the same constants to each side.

$y-2+36=x^{2}+12x+36$

$y+34=x^{2}+12x+36$

Rewrite as perfect squares

$y+34=(x+6)^{2}$

$y=(x+6)^{2}-34$

The vertex is the point (-6,-34)