Answer:
We conclude that the equation in slope-intercept form of the line that passes through (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
where
Given the line
y = -3/4x + 1
comparing with the slope-intercept form of the line equation
The slope = m = -3/4
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -3/4
Thus, the slope of the new perpendicular line = – 1/(-3/4) = 4/3
Using the point-slope form
where m is the slope of the line and (x₁, y₁) is the point
substituting the values of the slope = 4/3 and the point (12, 9)
Add 9 to both sides
Therefore, we conclude that the equation in slope-intercept form of the line that passes through (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:
Answer:
D
Step-by-step explanation:
The second option ADV and EDA
First distribute the negative through the parenthesis on the left and the 2 on the right.
-5 -15y +1 = 14y -32 - y
Combine like terms on the right and left
-4 -15y = 13y -32
Now move the variables to one side and the constants to the other.
Subtract 13y from both sides
-4 -28y = -32
Add 4 to both sides
-28y = -28
Divide both sides by -28
y = 1
-73 i think it is i might be wrong