Answer:
The volume of nitrogen oxide formed is 35.6L
Explanation:
The reaction of nitric acid with copper is:
Cu(s) + 4HNO₃ → Cu(NO₃)₂ + 2NO₂(g) + 2H₂O(l)
Moles of copper are:
Moles of nitric acid are:
As 1 mol of Cu reacts with 4 moles of HNO₃:
0.697 mol Cu × (4mol HNO₃ / 1mol Cu) = 2.79 moles of HNO₃ will react. That means Cu is limiting reactant.
Moles of NO₂ produced are:
0.697 mol Cu × (2mol NO₂ / 1mol Cu) = <em>1.394 moles of NO₂</em>
Using PV = nRT
<em>Where P is pressure (735torr / 760 = 0.967atm); n are moles (1.394mol); R is gas constant (0.082atmL/molK); T is temperature (28.2°C + 273.15 = 301.35K). </em>
Thus, volume is:
V = nRT / P
V = 1.394mol×0.082atmL/molK×301.35K / 0.967atm
V = 35.6L
<em>The volume of nitrogen oxide formed is 35.6L</em>
Hey there!
Get molar mass of C₆H₁₀S:
C: 6 x 12.01
H: 10 x 1.008
S: 1 x 32.065
------------------
144.205 g
To find the amount of moles we have, divide 22.4 by 144.205. Get 0.155.
There are 0.155 moles of S.
Hope this helps!
The ratio Potassium : Selenium is 39:78 but that can be simplified to 13:26 (divide each by 3) in grams. Hope this helps.
Which list of elements contains a metal, a metalloid, and a nonmetal?(1) Zn, Ga, Ge (3) Cd, Sb, I(2) Si, Ge, Sn (4) F, Cl, Br
Sladkaya [172]
3) Cd . Sb . I
<span>look at the periodic chart- if the element is on the right it is a nonmetal, if it is on the left its a metal, and if it is in between it is a metalloid</span>
Answer: NH3 and NH3
Explanation:
If hydrogen is bonded to a highly electronegative element, a strong dipole-dipole attraction is set up with strength ten times greater than normal dipole-dipole attractions, and it is crystal clear that electronegativity increase from left to right across the period and it decreases down the group. Nitrogen being electronegative more than Oxygen will exhibit a greater dipole-dipole attraction. As such, NH3 and NH3 is the right answer.