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Lina20 [59]
3 years ago
6

How can chemical weathering contribute to physical weathering?

Chemistry
1 answer:
lora16 [44]3 years ago
5 0

A-leads to the abrasion of rocks and minerals

A-dense vegetation cover

True

Explanation:

Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.

Agent of weathering are wind, water and glacier.

Chemical weathering contributes to physical weathering in that it leads to the abrasion of rocks and minerals.

During chemical weathering, a rock chemically combines with materials in the environment and weakens it.

When physical weathering processes are induced, grains produced independently weakening of bonds in rocks grind against one another and wears each other off.

An area with a dense vegetation cover undergoes rapid chemical weathering:

  • Plant roots penetrates deep into the rock and increases the surface area of chemical action.
  • Plants produce chemicals that combines with rocks and causes them to decay.
  • Since the area is always moist, chemical action becomes more severe.

Buildings and statues made of stone are subjected to the same degree of weathering as rocks exposed naturally.

This is true.

Statues and buildings weather just like rocks we find in nature.

It is the same sunshine and rain that impacts rocks that also impacts buildings and statues.

So they degrade at the same rate except they are protected.

learn more:

Erosion brainly.com/question/2473244

#learnwithBrainly

You might be interested in
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
3 years ago
Read 2 more answers
Help help help help help
dimaraw [331]

Answer:

neon gas

Explanation:

neon is a noble gas, meaning it has a full outer shell of elections. this means it is stable and is very unlikely to have a reaction with another substance.

7 0
2 years ago
I'll mark brainliest!! :)
Viefleur [7K]
I believe the answer is C, AgBr. I hope this helps
3 0
3 years ago
A chemist wants to examine specific chemical reactions and isolate certain products using a controlled experiment. How would the
professor190 [17]

Answer:

in a laboratory

Explanation:

A controlled experiment refers to the one where everything is an experiment except a single variable is held constant. A collection of information is typically taken as a control group, which is generally the ordinary state, and another group is analyzed( such as chemical reaction as per the question) in which all conditions are similar to the control group except for the variable under examination. The main benefit of a controlled experiment is that confusion over the accuracy of the results can be eliminated more easily.

6 0
3 years ago
A mixture of C3H8 and C2H2 has a mass of 2.8 g. It is burned in excess O2 to form a mixture of water and carbon dioxide that con
astraxan [27]

Answer:

The mass of C2H2 in the mixture is 0.56gram using the ratio of carbon in the products contributed by the C2H2.

Explanation:

The balanced equation for the reaction is: C3H8 + 2C2H2 + 10O2 >> 7CO2 + 6H2O.

From the reaction, we know that the oxygen was in excess, this will make the Carbon sources the limiting agents in the reaction. The details of the reaction showed that the ratio of water to the carbon dioxide is 1.6:1. This also means that the expected mole of carbon dioxide will be 7/1.6, which is 3.75moles.

The individual balanced equation of reaction is:

C3H3 +5O2 >> 3CO2 + 4H2O

and 2C2H2 + 5O2 >>4CO2 + 2H2O. From this one can quickly tell that the propane is in sufficient supply as it produces 3 moles of CO2 out of the expected 3.75 moles obtained above. Leaving 0.75moles of CO2 to the ethyne.

The mass of ethyne in the mixture will therefore be: 0.75/3.75 X 2.8 = 0.56g.

4 0
3 years ago
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