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Yuki888 [10]
3 years ago
12

While riding her bike to the ocean and back home 55 times, kimberly timed herself at 48min48⁢min, 48min48⁢min, 49min49⁢min, 46mi

n46⁢min, and 64min64⁢min. she had set a goal of averaging 5353 minutes for her rides. how many minutes will she need to spend on her sixth ride to attain her goal?
Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0
Total of 5 times = 48 + 48 + 49 + 46 + 64 = 255 mins

Goal:
Average = 53 mins
Total = 53 x 6 = 318 mins

6th ride = 318 - 255 = 63 mins

Answer: She needs to attain 63 mins for her 6th ride.




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Luba_88 [7]

Answer: Answers are in the steps read carefully!

Step-by-step explanation:

A) 3x^2 - 7x + 2 To factor this polynomial, you have to find two numbers that their product is 6 and their sum is -7.  The numbers -1 and -6 works out because -6 times -1 is 6  and -6 plus -1 is -7.

Now rewrite the polynomial as

3x^2 - 1x - 6x + 2   Now group it  

(3x^2 - 1x) (-6x+2)  Factor it by groups

x (3x -1)  -2(3x -1)    Now factor out 3x-1  

(3x -1) (x-2)  Done!    

B)  2x^2 - x -3     Now the same way.You will have two numbers that  their product is -6 and their sum is -1. You may be wondering how I get -6 .I get -6 by multiply the leading coefficient  2 by the constant -3.  The numbers -3 and 2 works out. Because -3 times 2 is -6 and -3 plus 2 is -1.

 Rewrite the polynomial as

2x^2 +2x - 3x -3     GRoup them and factor them

(2x^2 + 2x)  (-3x-3)  

2x(x+1) -3(x+1)  Factor out x+1

(x+1) (2x -3) Done!  

C) 3x^2 - 16x - 12   Find two numbers that their product is -36 and their sum is -12. The numbers -18 and 2 works out because -18 times 2 is -36 and -18 plus 2 is -16.

Rewrite the polynomial

3x^2 +2x -18x - 12   GRoup them

 (3x^2 + 2x)   (-18x - 12)   Factor them

x (3x +2) -6(3x +2)  Factor out 3x+2

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6 0
4 years ago
A fair coin is flipped three times. Events A and B are defined as: A: there are at least two consecutive heads somewhere in the
Vaselesa [24]

Answer:

2 / 7

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Coin flipped 3 times has following outcomes, of heads 'H' & Tails 'T'

HHH , TTT , HTT, THT , TTH , THH , HTH , HHT  = total outcomes

P (A) = 2 consecutive heads , P (B) = atleast one tail

P (A) = 2 outcomes ( HHH , HHT , THH ) / total 8 outcomes = 3 / 8

P (B) = 7 outcomes (all except HHH) / total 8 outcomes = 7 / 8

P (A | B) = P ( A ∩ B ) / P (B)

P ( A ∩ B ) = P ( 2 consecutive heads & atleast one tail) / Total outcomes =   2 outcomes ( HHT , THH ) / total 8 outcomes = 2 / 8

So, P (A | B) = ( 2 / 8 ) /  ( 7 / 8 ) = 2 / 7

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3 years ago
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Answer: x=-2 y=2

Step-by-step explanation:

I decided that isolating the y value of the second equation is the best way to start solving.

I divide 3 from both sides to get y= (4-x)/3. With this, I can substitute into the first equation. 4x+3(4-x)/3)=-2.

The multiplying the 3 by the denominator three cancels each other out to make:

4x+4-x=-2.

We subtract 4 on both sides and then subtract x from 4x.

We end up with 3x=-6. Then, we divide both sides by 3.

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Now we substitute this into the second equation to solve.

3y=4-(-2)

This becomes 3y=4+2 which is 3y=6

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I hope you learned something :)

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IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

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The quotient is x^2-2x+3.

Therefore, the correct option is D.

7 0
3 years ago
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