Answer: x = 5
Step-by-step explanation:
Use Pythagorean's Theorem
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
By definition. The volume of the sphere is:
V = (4/3) * (pi) * (r ^ 3)
Where,
r: radius of the sphere.
Substituting values:
2254 pi = (4/3) * (pi) * (r ^ 3)
Clearing the radio we have:
r ^ 3 = (3/4) * (2254)
r = ((3/4) * (2254)) ^ (1/3)
r = 11.91255883
Then, the surface area is:
A = 2 * pi * r ^ 2
Substituting values:
A = 2 * 3.14 * (11.91255883) ^ 2
A = 891.6 m ^ 2
Answer:
The surface area of the sphere is:
b. 891.6 m ^ 2
The answer is D. Solve for the first variable in one of the equations, then substitute the result into the other equation.
Answer:
Step-by-step explanation:
- 4^8/(4^2)^-3 ÷ 4^4 = 4^n
- 4^8/4^-6 ÷ 4^4 = 4^n
- 4^(8 - (-6) - 4) = 4^n
- 4^10 = 4^n
- 10 = n
- n = 10
