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8090 [49]
2 years ago
6

If AD = 6x – 4 and AC = 4x – 3, find CD.

Mathematics
1 answer:
murzikaleks [220]2 years ago
8 0

Answer:

Since C is the mid point,

therefore, (6x - 4)/2 = 4x-3

=> 6x - 4 = 2X(4x-3) = 8x - 6

=> 6x - 8x = -6 + 4

=> -2x = -2

=> x = (-2)/(-2) = 1

Hence, CD = AC = 4x - 3 = 4X1 - 3 = 1

Step-by-step explanation:

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What is 2 thirds of 60
Mkey [24]
You have to set up a proportion so 2 over 3= x over 60. So multiply 2 times 60= 120 divided by 3 which is 40
6 0
3 years ago
2m3 of soil containing 28% silt was mixed into 1 m3 of soil containing 13% of silt. What is the silt content mixture?
Leto [7]
Alright
so
28% of 2 m³=0.28 times 2=0.56 m³ of silt in the first mixture

13% of the 1 m³=0.13 times 1=0.13 m³ of silt in 2nd

total is 0.56 m³+0.13 m³=0.69 m³ of silt
and the total is 2m³+1m³=3m³

so
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answer is D
6 0
3 years ago
the perimeter of a rectangle is 70m. What are the dimensions that will produce the maximum area of such a rectangle
rusak2 [61]

Answer:

17.5, divide 70 by 4

Step-by-step explanation:

what i said above

3 0
3 years ago
5w²-5w=0 . -10n²+35n=0 . 2x²+15x=0 . 18c²+6c=0 . -32y²-24y=0
love history [14]

5 {w}^{2}  - 5w = 0\Leftrightarrow 5w(w - 1) = 0\Leftrightarrow w = 0 \: \vee \: w = 1 \\  - 10 {n}^{2}  + 35n = 0\Leftrightarrow  - 5n(2n - 7) = 0\Leftrightarrow n = 0 \: \vee \: n =  \frac{7}{2}  \\ 2 {x}^{2}  + 15x = 0\Leftrightarrow x(2x + 15) = 0\Leftrightarrow x = 0 \: \vee \: x =  \frac{15}{2}  \\ 18 {c}^{2}  + 6c = 6c(3c + 1) = 0\Leftrightarrow c = 0  \: \vee \: c =  -  \frac{1}{3}  \\  - 32 {y}^{2}  - 24y = 0\Leftrightarrow  - 8y(4y + 3) = 0\Leftrightarrow y = 0 \:\vee \: y =  -  \frac{3}{4}  \\ 3 {k}^{2}  = 6k\Leftrightarrow k = 0 \: \vee \: k = 2 \\ 6 {h}^{2}  = 3h\Leftrightarrow h = 0 \: \vee \: h =  \frac{1}{2}  \\ 4 {s}^{2}  = 10s\Leftrightarrow s = 0 \: \vee \: s =  \frac{5}{2}  \\  - 42 {z}^{2}  = 14z\Leftrightarrow z = 0 \:\vee \: z =  -  \frac{1}{3}

6 0
3 years ago
Compare the subtraction problems (6 8 − 5 8 = 1 8 ) and (6 9 − 7 9 = −1 9 ). Why is the answer to the first problem positive and
kherson [118]

Answer:

In the second problem, the first fraction is less than the second fraction.

If you subtract a lesser number from a greater number, the answer is positive.

If you subtract a greater number from a lesser number, the answer is negative.

Step-by-step explanation:

Hope this helps

Sorry if it was late

7 0
3 years ago
Read 2 more answers
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