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melomori [17]
4 years ago
9

Please help!! What is 5/6 + 16/6

Mathematics
2 answers:
aivan3 [116]4 years ago
7 0
It is 2 and 2/9 (2.22222222...)
Nana76 [90]4 years ago
3 0
Your correct answer is 13 3/6
5 x 16 = 80
80/6 is improper so we will make it
13 3/6

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−3(y+5)=15 someone please help me with this question my assignment is already late
AnnyKZ [126]

Answer: -10

Step-by-step explanation:

Simplifying

-3(y + 5) = 15

Reorder the terms:

-3(5 + y) = 15

(5 * -3 + y * -3) = 15

(-15 + -3y) = 15

Solving

-15 + -3y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + -3y = 15 + 15

Combine like terms: -15 + 15 = 0

0 + -3y = 15 + 15

-3y = 15 + 15

Combine like terms: 15 + 15 = 30

-3y = 30

Divide each side by '-3'.

y = -10

Simplifying

3 0
3 years ago
Fill in the spaces to complete the equality:<br><br> n²+7n=n(__+__)
jolli1 [7]

Answer:

n²+7n=n(7+n)

Step-by-step explanation:

Using the distributive property on the right side of the equation will make both sides of the equality equal.

3 0
3 years ago
Read 2 more answers
What set of transformations is performed on triangle ABC to form triangle A'B'C'?
jonny [76]
In order to answer this question, you would need to provide a coordinate, but since this question lacks that, I will explain transformations. Transformations are like moving an object throughout a room, in this case, the room is a graph. The Y coordinate
(X, Y) is moving things higher or lower, or in this case up and down the graph. The X coordinate (X, Y) is moving things forward and backwards, or left and right on the graph. So in order to find your Transformation, you need to take what was your item's original position, it's X and Y locations, and subtract from that your new location.

Here's an example, if I had a triangle with sides and corners labeled A, B, and C or for short, triangle ABC, if A is located at (1 , 0), B is located at (3 , 3) , and C is located at ( 5 , 0) what is its new transformation if it is moved up 3 and right 1?

You would then add 1 to each angle's X coordinate and add 3 to each angle's Y coordinate. Resulting in this:
A (2 , 3)

B (4 , 6)

C (6 , 3)

I hope this was helpful
5 0
3 years ago
what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
liberstina [14]

The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

4 0
2 years ago
About how far apart do aesha and Josh live​
Vesnalui [34]

Answer:

D. about 8.5 mi

Step-by-step explanation:

To go from Aesha to Josh, you go 6 units right and 6 units up.

Each unit is a mile, so you go 6 miles right and 6 miles up.

Think of each 6 mile distance as a leg of a right triangle, and the direct distance from one place to the other as the hypotenuse of the right triangle. Use the Pythagorean theorem to find the length of the hypotenuse.

a^2 + b^2 = c^2

The 6-mile legs are a and b. c is the hypotenuse.

(6 mi)^2 + (6 mi)^2 = c^2

c^2 = 36 mi^2 + 36 mi^2

c^2 = 72 mi^2

c = sqrt(72) mi

c = sqrt(36 * 2) mi

c = 6sqrt(2) mi

c = 6(1.4142) mi

c = 8.5 mi

8 0
4 years ago
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