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Juliette [100K]
3 years ago
10

PLZZZ HELPP NOWWWWW......

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

3.5% of 20, (0.035)*20, and 7% of 10

Step-by-step explanation:

Converting the mixed number (3 1/2) to a decimal yields 3.5, so 3.5% of 20 is correct.

3 1/2 is not equal to 3 1/2%, so 3 1/2 * 20 is not correct.

Converting the percentage to a decimal yields .035 which makes .35 too large, so (0.35) * 20 is not correct.

Changing the percentage to a decimal yields .035, so (0.035) * 20 is correct.

If you divide 20 by 2, you get 10, and if you multiply 2 by 3 1/2, you get 7. The 2 remains part of the expression, so it is equal to 3 1/2 of 20.

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<u>Answer:</u>

<h2>94% of the money went to charities.</h2>

6 0
2 years ago
Name a pair of complementary angles.
allochka39001 [22]

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8 0
3 years ago
What is the volume of the ones that have it and how do I find the expression
kherson [118]

Answer:

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7 0
3 years ago
Given: ABCD trapezoid, BK ⊥ AD , AB=DC AB=8, AK=4 Find: m∠A, m∠B
Elis [28]

Answer:

m\angle B=m\angle C=120^{\circ}

m\angle A=m\angle D=60^{\circ}

Step-by-step explanation:

Trapezoid ABCD is isosceles trapezoid, because AB = CD (given). In isosceles trapezoid, angles adjacent to the bases are congruent, then

  • \angle A\cong \angle D;
  • \angle B\cong \angle C.

Since BK ⊥ AD, the triangle ABK is right triangle. In this triangle,  AB = 8, AK = 4. Note that the hypotenuse AB is twice the leg AK:

AB=2AK.

If in the right triangle the hypotenuse is twice the leg, then the angle opposite to this leg is 30°, so,

m\angle ABK=30^{\circ}

Since BK ⊥ AD, then BK ⊥ BC and

m\angle KBC=90^{\circ}

Thus,

m\angle B=30^{\circ}+90^{\circ}=120^{\circ}\\ \\m\angle B=m\angle C=120^{\circ}

Now,

m\angle A=m\angle D=180^{\circ}-120^{\circ}=60^{\circ}

7 0
3 years ago
okay so on my homework assignment it says find the area of a semicircle but we never went over finding the area of that. Can som
eimsori [14]
Okay so s semicircle hmm. Thats semi-of-a-circle. So half would be fine.  
Then do the equation set up for area of a CIRCLE not s spere. 
3 0
3 years ago
Read 2 more answers
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