4.7944 x 10^2 hope this helps!
Given the vertex of the parabola at point (2, -3):
The quadratic function in vertex form is:
f(x) = (x - 2)^2 - 3
where the vertex (h, k) is the minimum point = (2, -3).
Answer:
![P(x \le 21) = 0.69146](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29%20%3D%200.69146)
Step-by-step explanation:
The missing parameters are:
--- population
--- population mean
-- population standard deviation
Required
![P(x \le 21)](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29)
First, calculate the sample standard deviation
![\sigma_x = \frac{\sigma}{\sqrt n}](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%20n%7D)
![\sigma_x = \frac{16}{\sqrt {64}}](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%20%5Cfrac%7B16%7D%7B%5Csqrt%20%7B64%7D%7D)
![\sigma_x = \frac{16}{8}](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%20%5Cfrac%7B16%7D%7B8%7D)
![\sigma_x = 2](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%202)
Next, calculate the sample mean ![\bar_x](https://tex.z-dn.net/?f=%5Cbar_x)
![\bar x = \mu](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cmu)
So:
![\bar x = 20](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2020)
So, we have:
![\sigma_x = 2](https://tex.z-dn.net/?f=%5Csigma_x%20%3D%202)
![\bar x = 20](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2020)
![x = 21](https://tex.z-dn.net/?f=x%20%3D%2021)
Calculate the z score
![x = \frac{x - \mu}{\sigma}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7Bx%20-%20%5Cmu%7D%7B%5Csigma%7D)
![x = \frac{21 - 20}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B21%20-%2020%7D%7B2%7D)
![x = \frac{1}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
![x = 0.50](https://tex.z-dn.net/?f=x%20%3D%200.50)
So, we have:
![P(x \le 21) = P(z \le 0.50)](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29%20%3D%20P%28z%20%5Cle%200.50%29)
From the z table
![P(z \le 0.50) = 0.69146](https://tex.z-dn.net/?f=P%28z%20%5Cle%200.50%29%20%3D%200.69146)
So:
![P(x \le 21) = 0.69146](https://tex.z-dn.net/?f=P%28x%20%5Cle%2021%29%20%3D%200.69146)
To solve for the coefficient of variation you will need this formula:
CV = (SD/X) x 100
Where: CV = Coefficient of Variance
X = Mean/average
SD = Standard Deviation
To determine which one is more variable, just get the coefficient of both and compare.
AGE SALARY
CV = (6/55) x 100 CV = (4,100/37,000) x 100
= 10.90 = 11.08
Based on the results, salary is more variable because 10.90<11.08.
Answer:
6 yards
Step-by-step explanation:
<u>Perimeter of a rectangle: 2a + 2b</u>
2(33) + 2(75)
66 + 150
216 inches
216/12 gives us feet
18/3 gives us yards
6 yards
Answer: 6 yards