$\dfrac{n!}{r!(n-r)!}\quad \text{where n is the quantity of items and r is the quantity chosen}\\\\\text{In this problem, there are 10 numbers (n = 10) and 7 to be chosen (r = 7)}\\\\_{10}C_{7}=\dfrac{10!}{7!(10-7)!}\\\\.\qquad=\dfrac{10!}{7!3!}\\\\.\qquad=\dfrac{10\times 9\times 8\times 7!}{7!\times 3\times 2\times 1}\\\\.\qquad=10\times 3\times 4\\\\.\qquad=120$

7 0

3 years ago

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Explain how you know if a system of equations has one solution, no solutions, or infinitely many solutions. Write your answers (

Nataliya [291]

Answer:

Written Below.

Step-by-step explanation:

A system of linear equations has one solution when the graphs intersect at a point. A system of linear equations has no solution when the graphs are parallel. A system of linear equations has infinite solutions when the graphs are the exact same line.

(This uses graphing.)

Sidenote: I hope this helps! :)

7 0

3 years ago

A paper company needs to ship paper to a large printing business. The paper will be

slamgirl [31]

45x+75y=1410 i hope this helps bc i’m pretty sure i’m learning the same thing but i hope this helps

3 0

3 years ago