A = P*e^(rt)
Here,
A = $4000*e^(0.051*2) = $4000*e^1.02 = $4000(2.773) = $11092.78
Note: This seems very high to me.
Answer:
A: 22
Step-by-step explanation:
2The interquartile range begins at 45 and ends at 67. All you need to do is subtract 45 drom 67, and you get 22.
16. 4 (9*4=36)
17. 6 (6*11=66)
18. 8 (10*8=80)
19. 9 (9*5=45)
20. 48 (4*12=48)
21. 13 (13*2=26)
I would think it to be A because 8/12 can be simplified into 3/4
