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3 years ago

Use fraction multiplication to find the percent of a number.

Mathematics

1 answer:

fgiga [73]3 years ago

4 0

Answer:

Step-by-step explanation:

30 x .2

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Twice the quantity of 4d increased by 9 is 33.

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play with my melons and drool my girl part

Step-by-step explanation:

it would feel so good and after i can make you com it will make you feel better

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3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

GaryK [48]

Explanation
: the answer is m=f

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3 years ago

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Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

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3 years ago

Pls help pls help i will award brainliest.

WINSTONCH [101]

Answer:

-24

Step-by-step explanation:

4a+8-a

a=-2

4(-2)+8-(-2)

-8+-16

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3 years ago

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Jarrett wants to buy a really cool car but it costs $4,350 and he doesn’t have a job. The only job he can find will pay him $7.2

den301095 [7]

Answer:

30 weeks

Step-by-step explanation:

7.25 x 20 = 1 WEEK

1 WEEK= 145$

4,350 divided by 145=30

30 weeks

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3 years ago