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sasho [114]
3 years ago
10

What is hyper transport

Computers and Technology
1 answer:
Nastasia [14]3 years ago
8 0

HyperTransport technology is a high-speed, low-latency, point-to-point link designed to increase the communication speed between integrated circuits in computers, servers, embedded systems, and networking and telecommunications equipment up to 48 times faster than some existing technologies.

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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

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System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

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// greater than which string (s2 or s3), or equal, print the result out

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// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

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System.out.println("They matched");

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// To do 5: Find the location of the first character 'g' in s1, print it out

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for (i = 0; i < s2.length(); ++i)

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break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

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int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

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} // end class StringLab9

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\bold{Answer:}

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