[ ASAP ! ]
Will give brainiest to the first correct answer
<3
2 answers:
Answer:
Step-by-step explanation:
{x-(-3/4)}^2=3^2
(x+3/4)^2=9
{(4x+3)/4}^2=9
(4x+3)^2/16=9
(4x+3)^2=9*16
16x^2+2*4x*3+3^2=144
16x^2+24x+9=144
16x^2+24x+9-144=0
16x^2+24x-135=0
We are given a circle which is centered at the point (-3,4) and has a radius of length 3.
We have to find the equation of the circle.
The equation of circle centered at (a,b) and radius r is-
Here a=-3 , b=4 and r=3
Hence, equation of circle is:
(x+3)^2 + (y-4)^2 = 3^2
(x+3)^2 + (y-4)^2 =9
Answer:
D
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k ) = (- 3, 4 ) and r = 3 , then
(x - (- 3))² + (y - 4)² = 3² , that is
(x + 3)² + (y - 4)² = 9 → D
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