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3 years ago

What numbers are a distance of 9 units from −5 on a number line?

Mathematics

2 answers:

pochemuha3 years ago

7 0

La respuesta da. 4 por que haci me dio

ValentinkaMS [17]3 years ago

7 0

So if you had a number line:
-14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
^^ ^^^ go over 9 units ^^
(right and left)
((+) means positive and (-)means negative) hope I helped!

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Someone can you please help me on number 74

lisabon 2012 [21]

Answer:

9t^3 +t^2

Step-by-step explanation:

The perimeter of the figure is the sum of the lengths of the sides. The side lengths are represented by the polynomials shown, so the perimeter (P) is their sum:

P = (4t^3 -5) + (4t^3 -5) + (t^2 +9) + (t^3 -t^2 -11) + (t^2 +12)

Rearranging to group like terms:

P = (4t^3 +4t^3 +t^3) + (t^2 -t^2 +t^2) + (-5 -5 +9 -11 +12)

P = 9t^3 +t^2

The perimeter of the figure is represented by the polynomial 9t^3 +t^2.

5 0

3 years ago

Read 2 more answers

If a bike is $125 how much will it be when its discounted by 20%

weeeeeb [17]

Answer:

160 pages.

Step-by-step explanation:

That is 125 - 0.20 * 125

= 125 - 25

= 160 pages.

6 0

3 years ago

Read 2 more answers

What is the mass (in grams) of 8.11×1026 CO2 molecules?

Kobotan [32]

Answer:

It is 59,275.74 grams

Step-by-step explanation:

• Molecular mass of carbon dioxide

$= (12 \times 1) + (16 \times 2) \\ = 12 + 32 \\ = 44 \: g$

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

${ \sf{6.02 \times {10}^{23} \: molecules = 44 \: g }}\\ { \sf{8.11 \times {10}^{26} \: molecules =( \frac{8.11 \times {10}^{26} }{6.02 \times {10}^{23} } \times 44) \: g}} \\ \\ = { \boxed{ \boxed{ \bf{59275.7 \: \: g}}}}$

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2 years ago

Please help me with these two math questions! Thank you ! :)

notka56 [123]

I think it might be c hope that helps you

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2 years ago

Diano4ka-milaya [45]

X+y=7 and 16x+25y=148

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3 years ago