Suppose that the distribution of touchdown passes (in football) is normally distributed with a mean of 250 feet and a standard d eviation of 50 feet. We randomly sample 49 touchdowns. What is the probability that the 49 touchdowns traveled an average of less than 245 feet? Please explain how you derived your answer.
1 answer:
Answer: 0.2420
Step-by-step explanation:
Given: Mean :
Standard deviation :
Sample size :
The formula to calculate z is given by :-
For x= 245
The P Value =
Hence, the probability that the 49 touchdowns traveled an average of less than 245 feet= 0.2420
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m∠E =
Data
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