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scoray [572]
3 years ago
14

Suppose that the distribution of touchdown passes (in football) is normally distributed with a mean of 250 feet and a standard d

eviation of 50 feet. We randomly sample 49 touchdowns.
What is the probability that the 49 touchdowns traveled an average of less than 245 feet? Please explain how you derived your answer.
Mathematics
1 answer:
Ahat [919]3 years ago
8 0

Answer: 0.2420

Step-by-step explanation:

Given: Mean : \mu = 250 \text{ feet}

Standard deviation : \sigma =50\text{ inch}

Sample size : n=49

The formula to calculate z is given by :-

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x= 245

z=\dfrac{245-250}{\dfrac{50}{\sqrt{49}}}=-0.7

The P Value =P(Z

Hence, the probability that the 49 touchdowns traveled an average of less than 245 feet= 0.2420

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ANSWER

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EXPLANATION

To solve this equation we have to apply the property of the logarithm of the base,

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\ln e^{4x}=\ln 133

Now we apply the property of the logarithm of a power,

\log a^b=b\log a

In our equation,

\begin{gathered} 4x\ln e^{}=\ln 133 \\ 4x^{}=\ln 133 \end{gathered}

Then divide both sides by 4 and solve,

\begin{gathered} \frac{4x^{}}{4}=\frac{\ln 133}{4} \\ x\approx1.2226 \end{gathered}

The solution to this equation is x = 1.2226, rounded to four decimal places.

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1 year ago
How many lines of symmetry does this figure have<br> A 1<br> B, 2<br> C. 3<br> D, 4
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A.1

Step-by-step explanation:

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Step-by-step explanation:

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